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<title>sane-devel: Re: SANE &amp; exposure times</title>
<h1>Re: SANE &amp; exposure times</h1>
<b>Ewald R. de Wit</b> (<a href="mailto:ewald@pobox.com"><i>ewald@pobox.com</i></a>)<br>
<i>Thu, 29 Jul 1999 15:58:46 +0200</i>
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Didier Carlier (<a href="mailto:Didier.Carlier@sema.be">Didier.Carlier@sema.be</a>) wrote:<br>
<p>
<i>&gt; What is the meaning of an RGB value divided by a time ? Nothing says </i><br>
<i>&gt; for instance that the sensitivity of the detectors is the same for all</i><br>
<i>&gt; colors so that even for a picture that looks perfectly grey, you would get </i><br>
<i>&gt; completely different values for the quotients.</i><br>
<p>
I was thinking of the 'normalized' exposure times that have been<br>
corrected for these hardware issues (not the the physical exposure<br>
times given in say milliseconds). So a R:G:B of 1:1:1 should leave<br>
gray gray.<br>
<p>
<i>&gt; I'm just curious to understand in what application that division makes sense.</i><br>
<p>
The main use is for scanning negatives. For negatives, density of blue<br>
is ~3x that of red, and that of green is ~2x that of red (hence the<br>
orange color of the negative mask). So if you scan with 1:1:1 exposure<br>
time, the green channel will only use 1/2 of it's full range. In other<br>
words, you have lost one bit of what is basically your luminance. The<br>
blue channel is filled for only 1/3 and this poor blue definition can<br>
also be very visible to the human eye.<br>
<p>
All this can be solved by scanning with a 1:2:3 exposure so that the<br>
full range of all channels is utilized.<br>
<p>
<pre>
--
-- Ewald
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<p>
<pre>
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<li> <b>Next message:</b> <a href="0215.html">Jens Scheithauer: "scanimage and HP scanners"</a>
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<li> <b>In reply to:</b> <a href="0211.html">Didier Carlier: "Re: SANE &amp; exposure times"</a>
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<li> <b>Next in thread:</b> <a href="0212.html">Andreas Rick: "Re: SANE &amp; exposure times"</a>
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