kopia lustrzana https://github.com/Podcastindex-org/podcast-namespace
minor improvements to clarity
rodzic
6ec1a02ae8
commit
04d06c3e8d
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@ -227,7 +227,7 @@ the player to your app, and for which nothing already exists, add your own.
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A given recipient will receive
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A given recipient will receive
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```
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```
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Payment amount * Interval payout * Interval count
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(Payment amount) * (Interval payout) * (Interval count)
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```
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```
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`Payment amount` is calculated differently depending on whether `fee` is `true` of `false`.
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`Payment amount` is calculated differently depending on whether `fee` is `true` of `false`.
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@ -365,7 +365,7 @@ Interval payout: **1000 sats**
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<podcast:valueRecipient
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<podcast:valueRecipient
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name="D"
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name="D"
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type="node"
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type="node"
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address="309e2bd74dadb4a50c3be632a5068cbc820d520635acc5c527a2171ab6cab43a9c"
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address="039e2bd74dadb4a50c3be632a5068cbc820d520635acc5c527a2171ab6cab43a9c"
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split="4"
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split="4"
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fee="true"
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fee="true"
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/>
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/>
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@ -384,7 +384,7 @@ Interval payout: **2500 sats**
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1. `fee=true` recipients are paid first:
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1. `fee=true` recipients are paid first:
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- Recipient `C` gets a payment of 400 sats (calculated using $2500 \cdot 0.16 = 400$)
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- Recipient `C` gets a payment of 400 sats (calculated using $2500 \cdot 0.16 = 400$)
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- Recipient `D` gets a payment of 100 sats (calculated using $2500 \cdot 0.04 = 100$)
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- Recipient `D` gets a payment of 100 sats (calculated using $2500 \cdot 0.04 = 100$)
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2. After that, `fee=false` recipients distribute the remaining amount of 2000 sats (calculated using $2500 - 400 - 100 = 2000$)
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2. After that, `fee=false` recipients get the remaining amount of 2000 sats (calculated using $2500 - 400 - 100 = 2000$):
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- Recipient `A` gets a payment of 1010 sats (calculated using $2000 \cdot \dfrac{101}{101 + 99} = 1010$)
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- Recipient `A` gets a payment of 1010 sats (calculated using $2000 \cdot \dfrac{101}{101 + 99} = 1010$)
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- Recipient `B` gets a payment of 990 sats (calculated using $2000 \cdot \dfrac{99}{101 + 99} = 990$)
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- Recipient `B` gets a payment of 990 sats (calculated using $2000 \cdot \dfrac{99}{101 + 99} = 990$)
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