libdspl-2.0/dspl/src/dft/dft.c

193 wiersze
5.7 KiB
C
Czysty Wina Historia

This file contains ambiguous Unicode characters!

This file contains ambiguous Unicode characters that may be confused with others in your current locale. If your use case is intentional and legitimate, you can safely ignore this warning. Use the Escape button to highlight these characters.

/*
* Copyright (c) 2015-2019 Sergey Bakhurin
* Digital Signal Processing Library [http://dsplib.org]
*
* This file is part of libdspl-2.0.
*
* is free software: you can redistribute it and/or modify
* it under the terms of the GNU Lesser General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* DSPL is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public License
* along with Foobar. If not, see <http://www.gnu.org/licenses/>.
*/
#include <stdlib.h>
#include <math.h>
#include "dspl.h"
#ifdef DOXYGEN_ENGLISH
/*! ****************************************************************************
\ingroup DFT_GROUP
\fn int dft(double* x, int n, complex_t* y)
\brief Discrete Fourier transform of a real signal.
The function calculates the \f$ n \f$ -point discrete Fourier transform
real signal \f$ x (m) \f$, \f$ m = 0 \ldots n-1 \f$. \n
\f[
Y (k) = \sum_ {m = 0} ^ {n-1} x (m)
\exp \left (-j \frac {2 \pi} {n} m k \right),
\f]
where \f$ k = 0 \ldots n-1 \f$.
\param [in] x
Pointer to the vector of the real input signal \f$ x (m) \f$,
\f$ m = 0 \ldots n-1 \f$. \n
The size of the vector is `[n x 1]`. \n \n
\param [in] n
The size of the DFT \f$ n \f$
(the size of the vectors of the input signal and the result of the DFT). \n \n
\param [out] y
Pointer to the complex vector of the DFT result \f$ Y (k) \f$,
\f$ k = 0 \ldots n-1 \f$.
The size of the vector is `[n x 1]`. \n
Memory must be allocated. \n \n
\return
`RES_OK` if the DFT is calculated successfully. \n
Otherwise, \ref ERROR_CODE_GROUP "error code".
An example of using the `dft` function:
\include dft_test.c
The result of the program:
\verbatim
y [0] = 120.000 0.000
y [1] = -8.000 40.219
y [2] = -8.000 19.314
y [3] = -8.000 11.973
y [4] = -8.000 8.000
y [5] = -8.000 5.345
y [6] = -8.000 3.314
y [7] = -8.000 1.591
y [8] = -8.000 0.000
y [9] = -8.000 -1.591
y [10] = -8.000 -3.314
y [11] = -8.000 -5.345
y [12] = -8.000 -8.000
y [13] = -8.000 -11.973
y [14] = -8.000 -19.314
y [15] = -8.000 -40.219
\endverbatim
\note
This function performs the DFT calculation using the naive method and
requires \f$ n ^ 2 \f$ complex multiplications. \n
To increase the calculation speed, it is recommended to use
fast Fourier transform algorithms.
\author Bakhurin Sergey www.dsplib.org
**************************************************************************** */
#endif
#ifdef DOXYGEN_RUSSIAN
/*! ****************************************************************************
\ingroup DFT_GROUP
\fn int dft(double* x, int n, complex_t* y)
\brief Дискретное преобразование Фурье вещественного сигнала.
Функция рассчитывает \f$ n \f$-точечное дискретное преобразование Фурье
вещественного сигнала \f$ x(m) \f$, \f$ m = 0 \ldots n-1 \f$. \n
\f[
Y(k) = \sum_{m = 0}^{n-1} x(m)
\exp \left( -j \frac{2\pi}{n} m k \right),
\f]
где \f$ k = 0 \ldots n-1 \f$.
\param[in] x
Указатель на вектор вещественного входного сигнала \f$x(m)\f$,
\f$ m = 0 \ldots n-1 \f$. \n
Размер вектора `[n x 1]`. \n \n
\param[in] n
Размер ДПФ \f$n\f$ (размер векторов входного сигнала и результата ДПФ). \n \n
\param[out] y
Указатель на комплексный вектор результата ДПФ \f$Y(k)\f$,
\f$ k = 0 \ldots n-1 \f$.
Размер вектора `[n x 1]`. \n
Память должна быть выделена. \n \n
\return
`RES_OK` если ДПФ рассчитана успешно. \n
В противном случае \ref ERROR_CODE_GROUP "код ошибки".
Пример использования функции `dft`:
\include dft_test.c
Результат работы программы:
\verbatim
y[ 0] = 120.000 0.000
y[ 1] = -8.000 40.219
y[ 2] = -8.000 19.314
y[ 3] = -8.000 11.973
y[ 4] = -8.000 8.000
y[ 5] = -8.000 5.345
y[ 6] = -8.000 3.314
y[ 7] = -8.000 1.591
y[ 8] = -8.000 0.000
y[ 9] = -8.000 -1.591
y[10] = -8.000 -3.314
y[11] = -8.000 -5.345
y[12] = -8.000 -8.000
y[13] = -8.000 -11.973
y[14] = -8.000 -19.314
y[15] = -8.000 -40.219
\endverbatim
\note
Данная функция выполняет расчет ДПФ наивным методом и требует \f$ n^2 \f$
комплексных умножений. \n
Для увеличения скорости расчета рекомендуется использовать
алгоритмы быстрого преобразования Фурье.
\author Бахурин Сергей www.dsplib.org
***************************************************************************** */
#endif
int DSPL_API dft(double* x, int n, complex_t* y)
{
int k;
int m;
double divn;
double phi;
if(!x || !y)
return ERROR_PTR;
if(n<1)
return ERROR_SIZE;
divn = 1.0 / (double)n;
for(k = 0; k < n; k++)
{
RE(y[k]) = IM(y[k]) = 0.0;
for(m = 0; m < n; m++)
{
phi = -M_2PI * divn * (double)k * (double)m;
RE(y[k]) += x[m] * cos(phi);
IM(y[k]) += x[m] * sin(phi);
}
}
return RES_OK;
}