"""get a random port."""

# Copyright 2023 ipydrawio contributors
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.

import socket
import time
import urllib.request

from robot.api import logger


def get_unused_port() -> int:
    """Get an unused port by trying to listen to any random port.

    Probably could introduce race conditions if inside a tight loop.
    """
    sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    sock.bind(("localhost", 0))
    sock.listen(1)
    port = sock.getsockname()[1]
    sock.close()
    return port


def wait_for_url_status(
    url: str,
    status_code: int,
    interval_sec: float = 0.1,
    attempts: int = 100,
) -> bool:
    """Attempt to fetch from the URL until, or raise an."""
    response = None

    for _i in range(attempts):
        try:
            response = urllib.request.urlopen(url)
            if response.status == status_code:
                break
            logger.debug(response.status)
        except Exception:
            logger.debug(Exception)
        time.sleep(interval_sec)

    if not response or response.status != status_code:
        raise RuntimeError(
            f"{url} did return {status_code} within {interval_sec * attempts}s",
        )

    return True