socket examples: fix random ci failure on reading ipv6 address

dut.expect() returns groups of a matching regex, but could be truncated upon reading/buffering. fixed by forcing expect to acquire exactly 8 octets of IPv6 address, i.e. not supporting short-handed entries such as fe80::0000..
pull/5317/head
David Cermak 2020-05-11 08:20:43 +02:00 zatwierdzone przez bot
rodzic 26ab1c54ec
commit 5f4e2cf391
2 zmienionych plików z 4 dodań i 2 usunięć

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@ -65,7 +65,8 @@ def test_examples_protocol_socket(env, extra_data):
dut1.start_app()
ipv4 = dut1.expect(re.compile(r" IPv4 address: ([0-9]+\.[0-9]+\.[0-9]+\.[0-9]+)"), timeout=30)[0]
ipv6 = dut1.expect(re.compile(r" IPv6 address: ([0-9A-Fa-f\:]+)"), timeout=30)[0]
ipv6_r = r':'.join((r'[0-9a-fA-F]{4}',) * 8) # expect all 8 octets from IPv6 (assumes it's printed in the long form)
ipv6 = dut1.expect(re.compile(r' IPv6 address: ({})'.format(ipv6_r)), timeout=30)[0]
print("Connected with IPv4={} and IPv6={}".format(ipv4, ipv6))
# test IPv4

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@ -63,7 +63,8 @@ def test_examples_protocol_socket(env, extra_data):
dut1.start_app()
ipv4 = dut1.expect(re.compile(r" IPv4 address: ([0-9]+\.[0-9]+\.[0-9]+\.[0-9]+)"), timeout=30)[0]
ipv6 = dut1.expect(re.compile(r" IPv6 address: ([0-9A-Fa-f\:]+)"), timeout=30)[0]
ipv6_r = r':'.join((r'[0-9a-fA-F]{4}',) * 8) # expect all 8 octets from IPv6 (assumes it's printed in the long form)
ipv6 = dut1.expect(re.compile(r' IPv6 address: ({})'.format(ipv6_r)), timeout=30)[0]
print("Connected with IPv4={} and IPv6={}".format(ipv4, ipv6))
# test IPv4