diff --git a/README.win32 b/README.win32 index e4ac4f6bd..0cb0da14c 100644 --- a/README.win32 +++ b/README.win32 @@ -1,3 +1,17 @@ +Win32 builds +------------ + +MinGW +===== + +For DLLs compatible with MSVC++ cross-compiled from Linux with MinGW, see +the build-win32.sh script in the scripts/ directory and its companion README +file. + + +Cygwin +====== + From: "Mark J. Fine" Subject: [Hamlib-developer] Building under Cygwin for Windows (Mingw32) List-Archive: @@ -5,7 +19,7 @@ Date: Sun, 20 Jun 2004 15:25:24 -0400 -Found this to be helpful for building hamlib under Cygwin/Mingw32 for +Found this to be helpful for building hamlib under Cygwin/Mingw32 for linking with Windows apps: @@ -32,7 +46,7 @@ install it: Note: Don't run "make install" if you've already made a native Cygwin or Linux version of hamlib. It will interfere with the pkgconfig used for linking the hamlib library with a native Cygwin or Linux application. -In fact if you are building two versions, it's best to have one tree for +In fact if you are building two versions, it's best to have one tree for native Cygwin and another tree for cross-compiling with MingW32. This way you can avoid overwriting or corrupting any needed object files or libraries. @@ -54,8 +68,8 @@ Windows command window from the directory where you put all that stuff: > lib /def:libhamlib.def /machine:IX86 /name:libhamlib-1-2-2cvs-2 This will create libhamlib.lib and libhamlib.exp. This example is for -hamlib v1.2.2cvs-2. You will have to use the correct version of the -library in the "/name:" switch, above. +hamlib v1.2.2cvs-2. You will have to use the correct version of the +library in the "/name:" switch, above. REM: Using the (free) Microsoft Visual C++ Toolkit 2003, replace the "lib" command by "link /lib". @@ -64,7 +78,7 @@ libhamlib.lib and the .h includes from include/hamlib can now be used within any MSVC build (i.e., dream), but all the dlls must be put in the same directory or in PATH as the resulting .exe otherwise it won't find it. --- +-- Mark J. Fine Remington, Virginia, USA