DiFipp/include/math_utils.h

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// Copyright (c) 2019, Vincent SAMY
// All rights reserved.
// Redistribution and use in source and binary forms, with or without
// modification, are permitted provided that the following conditions are met:
// 1. Redistributions of source code must retain the above copyright notice,
// this list of conditions and the following disclaimer.
// 2. Redistributions in binary form must reproduce the above copyright notice,
// this list of conditions and the following disclaimer in the documentation
// and/or other materials provided with the distribution.
// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND
// ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
// WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
// DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR CONTRIBUTORS BE LIABLE FOR
// ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES
// (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES;
// LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND
// ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
// (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
// SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
// The views and conclusions contained in the software and documentation are those
// of the authors and should not be interpreted as representing official policies,
// either expressed or implied, of the FreeBSD Project.
#pragma once
#include <type_traits>
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namespace difi {
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// https://stackoverflow.com/questions/44718971/calculate-binomial-coffeficient-very-reliably
template <typename T>
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constexpr T Binomial(size_t n, size_t k)
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{
if (k > n)
return T(0);
else if (k == 0 || k == n)
return T(1);
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else if (k == 1 || k == n - 1)
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return T(n);
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else if (2 * k < n)
return Binomial<T>(n - 1, k - 1) * n / k;
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else
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return Binomial<T>(n - 1, k) * n / (n - k);
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}
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template <typename T>
constexpr T pow(T n, T k)
{
static_assert(std::is_integral_v<T>, "For integral values only, eitherwise, use std::pow");
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if (n == 0)
return (k == 0) ? 1 : 0;
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else if (k == 0)
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return T(1);
else
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return n * pow(n, k - 1);
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}
} // namespace difi